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(10x+49)^(1/2)+7=x
We move all terms to the left:
(10x+49)^(1/2)+7-(x)=0
We add all the numbers together, and all the variables
(10x+49)^(+1/2)-x+7=0
We add all the numbers together, and all the variables
-1x+(10x+49)^(+1/2)+7=0
We multiply all the terms by the denominator
-1x*2)+(10x+1+49)^(+7*2)=0
We add all the numbers together, and all the variables
-1x*2)+(10x+50)^14=0
We add all the numbers together, and all the variables
-1x*2)+(10x=0
Wy multiply elements
-2x^2=0
a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-4}=0$
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